Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:24Z

10γ² + 4γ + 3 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

det| 9 4 ; 1 10 | = 86

438K

d/dβ [β^11] = 11β^10

λ = h/p

186K

∫₀^∞ e^(-α²) dα = √π / 2

411K

3x² + 4x + 6 = 0

iħ ∂ψ/∂t = Ĥψ

448K

1n² + 7n + 3 = 0

22K

CaCO₃ → CaO + CO₂

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

6t² + 6t + 4 = 0

406K

d/dt [t^3] = 3t^2

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∇²n = 0

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∫₀^∞ e^(-t²) dt = √π / 2

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∑_{k=1}^{n} k = n(n+1)/2

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