Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:08Z

∑_{k=1}^{n} k = n(n+1)/2

∇ × E = −∂B/∂t

451K

11z² + 3z + 4 = 0

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det| 8 9 ; 3 9 | = 45

6x² + 6x + 1 = 0

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det| 9 4 ; 1 10 | = 86

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

det| 12 2 ; 2 13 | = 152

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\lim_{α\to 0} \frac{\sin α}{α} = 1

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det| 2 3 ; 3 3 | = -3

e^{i\pi} + 1 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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∇²t = 0

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d/dt [t^3] = 3t^2

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det| 8 9 ; 4 9 | = 36

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