Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 22:26Z

3n² + 7n + 7 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-ω²) dω = √π / 2

det| 3 6 ; 0 4 | = 12

186K

∇²γ = 0

411K

\frac{10}{6} \sum_{i=1}^{n} i^{2}

det| 9 4 ; 1 10 | = 86

448K

∫₀^∞ e^(-θ²) dθ = √π / 2

22K

d/dr [r^12] = 12r^11

E = mc²

459K

d/dt [t^3] = 3t^2

406K

d/dφ [φ^5] = 5φ^4

iħ ∂ψ/∂t = Ĥψ