Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:10Z

10y² + 2y + 6 = 0

∇ × E = −∂B/∂t

460K

∂ψ/∂β = 3ψ

438K

∫₀^∞ e^(-t²) dt = √π / 2

8ψ² + 7ψ + 0 = 0

186K

\lim_{r\to 0} \frac{\sin r}{r} = 1

411K

e^{i\pi} + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

d/dt [t^3] = 3t^2

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\lim_{β\to 0} \frac{\sin β}{β} = 1

459K

∂n/∂θ = 3n

406K

λ = h/p

∇ × E = −∂B/∂t

181K

det| 3 7 ; 2 4 | = -2

80K

d/dγ [γ^3] = 3γ^2

\frac{12}{6} \sum_{i=1}^{n} i^{2}

359K

CH₄ + 2O₂ → CO₂ + 2H₂O