Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:42Z

3γ² + 8γ + 4 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

PV = nRT

det| 3 7 ; 2 4 | = -2

186K

d/dt [t^3] = 3t^2

411K

det| 1 9 ; 5 2 | = -43

iħ ∂ψ/∂t = Ĥψ

448K

∇²r = 0

22K

ω = 2πf

2H₂ + O₂ → 2H₂O

459K

det| 1 4 ; 3 2 | = -10

406K

∇ × E = −∂B/∂t

181K

∫₀^∞ e^(-t²) dt = √π / 2

80K

8ψ² + 7ψ + 0 = 0

359K