Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:44Z

10y² + 2y + 6 = 0

d/dt [t^3] = 3t^2

460K

det| 7 9 ; 1 8 | = 47

438K

∫₀^∞ e^(-t²) dt = √π / 2

det| 5 2 ; 3 6 | = 24

186K

iħ ∂ψ/∂t = Ĥψ

411K

e^{i\pi} + 1 = 0

det| 9 8 ; 3 10 | = 66

448K

\frac{4}{9} \sum_{i=1}^{n} i^{2}

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∂x/∂ψ = 6x

459K

6r² + 3r + 1 = 0

406K

λ = h/p

det| 9 4 ; 1 10 | = 86

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∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

359K