Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:37Z

∇²t = 0

d/dt [t^3] = 3t^2

460K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

438K

det| 6 4 ; 3 7 | = 30

N₂ + 3H₂ ⇌ 2NH₃

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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ΔS ≥ 0

det| 9 8 ; 3 10 | = 66

448K

\frac{4}{6} \sum_{i=1}^{n} i^{2}

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1z² + 3z + 2 = 0

∂x/∂ψ = 6x

459K

λ = h/p

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7t² + 3t + 1 = 0

∇ × E = −∂B/∂t

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8ψ² + 7ψ + 0 = 0

80K

5φ² + 1φ + 1 = 0

359K