Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:01Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∂y/∂n = 5y

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 7 8 ; 4 8 | = 24

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

4φ² + 6φ + 2 = 0

det| 5 9 ; 7 6 | = -33

448K

\frac{4}{6} \sum_{i=1}^{n} i^{2}

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

459K

det| 7 4 ; 4 8 | = 40

406K

∇²ω = 0

e^{i\pi} + 1 = 0

181K

det| 7 6 ; 1 8 | = 50

80K

det| 4 2 ; 6 5 | = 8

359K