Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z
∇²n = 0
∫₀^∞ e^(-r²) dr = √π / 2
273K
9r² + 4r + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
108K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\frac{4}{6} \sum_{i=1}^{n} i^{2}
160K
11γ² + 3γ + 6 = 0
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
297K
∑_{k=1}^{n} k = n(n+1)/2
128K
det| 6 1 ; 3 7 | = 39
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
58K
N₂ + 3H₂ ⇌ 2NH₃