Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 13:33Z

F = ma

∑_{k=1}^{n} k = n(n+1)/2

273K

N₂ + 3H₂ ⇌ 2NH₃

263K

\lim_{β\to 0} \frac{\sin β}{β} = 1

11z² + 3z + 4 = 0

139K

∇²r = 0

108K

N₂ + 3H₂ ⇌ 2NH₃

det| 7 4 ; 4 8 | = 40

333K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

160K

e^{i\pi} + 1 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

439K

∑_{k=1}^{n} k = n(n+1)/2

413K

5z² + 8z + 3 = 0

297K

8x² + 2x + 7 = 0

128K