Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 03:05Z
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
F = ma
12θ² + 8θ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
448K
ω = 2πf
det| 9 4 ; 1 10 | = 86
459K
∑_{k=1}^{n} k = n(n+1)/2
406K
det| 4 2 ; 6 5 | = 8
181K
det| 7 8 ; 4 8 | = 24
80K
det| 5 2 ; 3 6 | = 24
455K