Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 01:03Z

12γ² + 2γ + 2 = 0

det| 7 4 ; 4 8 | = 40

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∇ × E = −∂B/∂t

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∑_{k=1}^{n} k = n(n+1)/2

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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∫₀^∞ e^(-θ²) dθ = √π / 2

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5φ² + 3φ + 0 = 0

det| 5 3 ; 7 6 | = 9

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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ΔS ≥ 0

N₂ + 3H₂ ⇌ 2NH₃

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∫₀^∞ e^(-y²) dy = √π / 2

F = G m₁m₂ / r²

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

Fe₂O₃ + 3CO → 2Fe + 3CO₂

N₂ + 3H₂ ⇌ 2NH₃