Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 00:34Z

\binom{n}{k} = \frac{n!}{k!(n-k)!}

∑_{k=1}^{n} k = n(n+1)/2

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N₂ + 3H₂ ⇌ 2NH₃

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d/dx [x^7] = 7x^6

det| 7 4 ; 4 8 | = 40

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11t² + 9t + 7 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

7r² + 8r + 5 = 0

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∫₀^∞ e^(-θ²) dθ = √π / 2

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CH₄ + 2O₂ → CO₂ + 2H₂O

e^{i\pi} + 1 = 0

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∂α/∂ω = 3α

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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