Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:48Z
∇²n = 0
∑_{k=1}^{n} k = n(n+1)/2
273K
\frac{4}{9} \sum_{i=1}^{n} i^{2}
263K
9r² + 4r + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
108K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
333K
11γ² + 3γ + 6 = 0
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
det| 6 1 ; 3 7 | = 39
\frac{2}{2} \sum_{i=1}^{n} i^{2}
404K
e^{i\pi} + 1 = 0