Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:23Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∇²β = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

iħ ∂ψ/∂t = Ĥψ

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

4φ² + 6φ + 2 = 0

6ω² + 4ω + 4 = 0

448K

\lim_{t\to 0} \frac{\sin t}{t} = 1

22K

∇ × E = −∂B/∂t

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

9ψ² + 7ψ + 3 = 0

181K

∫₀^∞ e^(-t²) dt = √π / 2

80K

8ψ² + 7ψ + 0 = 0

359K

2H₂ + O₂ → 2H₂O

455K