Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:38Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

438K

∫₀^∞ e^(-x²) dx = √π / 2

∂ψ/∂β = 3ψ

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

4φ² + 6φ + 2 = 0

F = ma

448K

8γ² + 1γ + 1 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\binom{n}{k} = \frac{n!}{k!(n-k)!}

459K

d/dt [t^3] = 3t^2

406K

∇²ω = 0

10ψ² + 5ψ + 0 = 0

181K

det| 10 2 ; 3 11 | = 104

80K

d/dr [r^2] = 2r^1

E = mc²

359K

det| 9 4 ; 1 10 | = 86

455K