Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 12:36Z
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
438K
4y² + 7y + 7 = 0
\lim_{α\to 0} \frac{\sin α}{α} = 1
411K
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
448K
6β² + 2β + 2 = 0
det| 7 4 ; 4 8 | = 40
459K
2φ² + 2φ + 5 = 0
5α² + 7α + 6 = 0
\lim_{n\to 0} \frac{\sin n}{n} = 1
det| 7 8 ; 0 8 | = 56
N₂ + 3H₂ ⇌ 2NH₃
AgNO₃ + NaCl → AgCl↓ + NaNO₃