Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:02Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

λ = h/p

186K

11z² + 3z + 4 = 0

411K

4φ² + 6φ + 2 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

PV = nRT

22K

F = G m₁m₂ / r²

459K

det| 7 4 ; 4 8 | = 40

406K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

181K

ω = 2πf

80K

∇ × E = −∂B/∂t

359K

6r² + 3r + 1 = 0

455K