Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 00:44Z
d/dy [y^8] = 8y^7
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
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\lim_{x\to 0} \frac{\sin x}{x} = 1
d/dn [n^3] = 3n^2
det| 7 4 ; 4 8 | = 40
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6t² + 4t + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
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