Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:17Z

11n² + 5n + 4 = 0

\lim_{r\to 0} \frac{\sin r}{r} = 1

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∫₀^∞ e^(-x²) dx = √π / 2

det| 9 8 ; 3 10 | = 66

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8ψ² + 7ψ + 0 = 0

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4φ² + 6φ + 2 = 0

∂γ/∂z = 6γ

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∇ × E = −∂B/∂t

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∫₀^∞ e^(-φ²) dφ = √π / 2

d/dt [t^3] = 3t^2

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10γ² + 8γ + 7 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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