Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 06:39Z

∑_{k=1}^{n} k = n(n+1)/2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

273K

9ψ² + 7ψ + 3 = 0

263K

e^{i\pi} + 1 = 0

det| 5 6 ; 2 6 | = 18

139K

∑_{k=1}^{n} k = n(n+1)/2

108K

2H₂ + O₂ → 2H₂O

∇ × E = −∂B/∂t

333K

8ψ² + 7ψ + 0 = 0

160K

det| 4 8 ; 0 5 | = 20

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

439K

5z² + 8z + 3 = 0

413K

det| 4 7 ; 7 5 | = -29

d/dt [t^3] = 3t^2

297K

12γ² + 9γ + 1 = 0

128K

10t² + 5t + 2 = 0

det| 1 6 ; 5 2 | = -28

F = ma