Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 16:54Z
10γ² + 4γ + 3 = 0
d/dβ [β^11] = 11β^10
∑_{k=1}^{n} k = n(n+1)/2
186K
∑_{k=1}^{n} k = n(n+1)/2
411K
3x² + 4x + 6 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
22K
CaCO₃ → CaO + CO₂
Fe₂O₃ + 3CO → 2Fe + 3CO₂
406K
det| 12 1 ; 5 13 | = 151
181K
det| 7 9 ; 1 8 | = 47
80K
det| 7 4 ; 4 8 | = 40
359K
∑_{k=1}^{n} k = n(n+1)/2
455K