Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:03Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

det| 11 9 ; 0 12 | = 132

411K

4φ² + 6φ + 2 = 0

F = G m₁m₂ / r²

448K

N₂ + 3H₂ ⇌ 2NH₃

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 7 4 ; 4 8 | = 40

459K

7γ² + 8γ + 3 = 0

406K

F = G m₁m₂ / r²

181K

e^{i\pi} + 1 = 0

80K

∇ × E = −∂B/∂t

359K