Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z

∇²n = 0

∑_{k=1}^{n} k = n(n+1)/2

273K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

263K

9r² + 4r + 1 = 0

E = mc²

139K

d/dt [t^3] = 3t^2

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

8ψ² + 7ψ + 0 = 0

333K

2n² + 4n + 0 = 0

160K

11γ² + 3γ + 6 = 0

det| 7 9 ; 1 8 | = 47

439K

∇ × E = −∂B/∂t

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

det| 8 9 ; 4 9 | = 36

297K

det| 5 2 ; 3 6 | = 24

128K

det| 6 1 ; 3 7 | = 39

∇²β = 0

404K

det| 4 8 ; 3 5 | = -4

58K

N₂ + 3H₂ ⇌ 2NH₃