Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 02:21Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

ω = 2πf

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iħ ∂ψ/∂t = Ĥψ

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\frac{8}{4} \sum_{i=1}^{n} i^{2}

F = G m₁m₂ / r²

297K

∂x/∂ψ = 6x

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N₂ + 3H₂ ⇌ 2NH₃

10ω² + 7ω + 4 = 0

48K

12γ² + 9γ + 1 = 0

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2α² + 3α + 3 = 0

\lim_{r\to 0} \frac{\sin r}{r} = 1

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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det| 10 7 ; 6 11 | = 68

det| 9 4 ; 1 10 | = 86

401K

F = G m₁m₂ / r²

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det| 5 2 ; 3 6 | = 24

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∇ × E = −∂B/∂t

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