Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z

∇²n = 0

∑_{k=1}^{n} k = n(n+1)/2

273K

det| 7 4 ; 4 8 | = 40

263K

9r² + 4r + 1 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

139K

N₂ + 3H₂ ⇌ 2NH₃

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∫₀^∞ e^(-x²) dx = √π / 2

333K

N₂ + 3H₂ ⇌ 2NH₃

160K

11γ² + 3γ + 6 = 0

∂γ/∂θ = 2γ

439K

e^{i\pi} + 1 = 0

413K

ΔS ≥ 0

297K

PV = nRT

128K

\lim_{r\to 0} \frac{\sin r}{r} = 1

404K