Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:57Z

11n² + 5n + 4 = 0

iħ ∂ψ/∂t = Ĥψ

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N₂ + 3H₂ ⇌ 2NH₃

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∫₀^∞ e^(-x²) dx = √π / 2

\frac{2}{2} \sum_{i=1}^{n} i^{2}

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8ψ² + 7ψ + 0 = 0

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4φ² + 6φ + 2 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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det| 4 7 ; 2 5 | = 6

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∫₀^∞ e^(-φ²) dφ = √π / 2

e^{i\pi} + 1 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

N₂ + 3H₂ ⇌ 2NH₃

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det| 11 5 ; 0 12 | = 132

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