Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 03:29Z
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
F = ma
det| 9 4 ; 1 10 | = 86
186K
det| 11 4 ; 5 12 | = 112
411K
12θ² + 8θ + 3 = 0
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
406K
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
181K
∇²x = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
E = mc²
9x² + 4x + 5 = 0
det| 2 6 ; 5 3 | = -24