Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:53Z

10y² + 2y + 6 = 0

3x² + 5x + 7 = 0

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det| 5 9 ; 7 6 | = -33

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∫₀^∞ e^(-t²) dt = √π / 2

det| 11 9 ; 0 12 | = 132

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det| 11 5 ; 0 12 | = 132

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e^{i\pi} + 1 = 0

∂y/∂n = 5y

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d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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λ = h/p

8ψ² + 7ψ + 0 = 0

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F = ma

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∇ × E = −∂B/∂t

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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