Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:47Z

11n² + 5n + 4 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

460K

\lim_{t\to 0} \frac{\sin t}{t} = 1

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇²β = 0

186K

7r² + 8r + 5 = 0

411K

4φ² + 6φ + 2 = 0

det| 9 4 ; 1 10 | = 86

448K

∑_{k=1}^{n} k = n(n+1)/2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

6t² + 6t + 4 = 0

459K

∇²r = 0

406K

∇²ω = 0

d/dt [t^3] = 3t^2

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

d/dr [r^2] = 2r^1

ΔS ≥ 0