Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:48Z
∇²n = 0
9r² + 4r + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
108K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
160K
11γ² + 3γ + 6 = 0
det| 11 5 ; 0 12 | = 132
439K
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
∫₀^∞ e^(-x²) dx = √π / 2
404K