Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 14:40Z
3γ² + 8γ + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
438K
PV = nRT
det| 11 4 ; 5 12 | = 112
186K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
411K
det| 1 9 ; 5 2 | = -43
det| 7 8 ; 4 8 | = 24
448K
ω = 2πf
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
459K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
406K
∂n/∂ψ = 6n
N₂ + 3H₂ ⇌ 2NH₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}