Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 11:32Z
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
det| 6 4 ; 3 7 | = 30
Fe₂O₃ + 3CO → 2Fe + 3CO₂
411K
ΔS ≥ 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
22K
∫₀^∞ e^(-t²) dt = √π / 2
459K
∫₀^∞ e^(-t²) dt = √π / 2
80K