Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 06:32Z

∑_{k=1}^{n} k = n(n+1)/2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∑_{k=1}^{n} k = n(n+1)/2

263K

e^{i\pi} + 1 = 0

∇²n = 0

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1θ² + 2θ + 6 = 0

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2H₂ + O₂ → 2H₂O

\frac{2}{2} \sum_{i=1}^{n} i^{2}

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∑_{k=1}^{n} k = n(n+1)/2

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det| 4 8 ; 0 5 | = 20

PV = nRT

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det| 9 4 ; 1 10 | = 86

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det| 4 7 ; 7 5 | = -29

6r² + 3r + 1 = 0

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d/dt [t^3] = 3t^2

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10t² + 5t + 2 = 0

det| 3 6 ; 0 4 | = 12

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det| 1 6 ; 5 2 | = -28

F = ma

∇ × E = −∂B/∂t