Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 03:07Z

e^{i\pi} + 1 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

∇ × E = −∂B/∂t

438K

F = ma

\lim_{t\to 0} \frac{\sin t}{t} = 1

186K

iħ ∂ψ/∂t = Ĥψ

411K

12θ² + 8θ + 3 = 0

8γ² + 1γ + 1 = 0

448K

det| 9 4 ; 1 10 | = 86

22K

ω = 2πf

det| 10 2 ; 3 11 | = 104

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

N₂ + 3H₂ ⇌ 2NH₃

1θ² + 2θ + 6 = 0

181K

10t² + 9t + 5 = 0

80K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

d/dt [t^3] = 3t^2

359K

E = mc²