Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:06Z

N₂ + 3H₂ ⇌ 2NH₃

∫₀^∞ e^(-θ²) dθ = √π / 2

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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9ψ² + 4ψ + 2 = 0

ΔS ≥ 0

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∑_{k=1}^{n} k = n(n+1)/2

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d/dβ [β^6] = 6β^5

det| 7 4 ; 4 8 | = 40

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∑_{k=1}^{n} k = n(n+1)/2

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det| 6 1 ; 4 7 | = 38

N₂ + 3H₂ ⇌ 2NH₃

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∇ × E = −∂B/∂t

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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10t² + 9t + 5 = 0

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e^{i\pi} + 1 = 0

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