Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 15:41Z
11n² + 5n + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
∫₀^∞ e^(-x²) dx = √π / 2
det| 8 9 ; 4 9 | = 36
186K
4φ² + 6φ + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
448K
det| 7 4 ; 4 8 | = 40
22K
∫₀^∞ e^(-φ²) dφ = √π / 2
∇²ω = 0
det| 7 9 ; 1 8 | = 47
181K
∫₀^∞ e^(-ψ²) dψ = √π / 2
80K
det| 5 2 ; 3 6 | = 24
455K