Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 03:29Z

e^{i\pi} + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

F = ma

det| 3 7 ; 2 4 | = -2

186K

iħ ∂ψ/∂t = Ĥψ

411K

12θ² + 8θ + 3 = 0

\frac{4}{9} \sum_{i=1}^{n} i^{2}

448K

10t² + 9t + 5 = 0

22K

ω = 2πf

7y² + 9y + 1 = 0

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

N₂ + 3H₂ ⇌ 2NH₃

181K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

80K

8ψ² + 7ψ + 0 = 0

359K