Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:24Z

∇²n = 0

∇ × E = −∂B/∂t

273K

PV = nRT

263K

9r² + 4r + 1 = 0

\frac{4}{6} \sum_{i=1}^{n} i^{2}

139K

∇²t = 0

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

PV = nRT

333K

det| 7 4 ; 4 8 | = 40

160K

11γ² + 3γ + 6 = 0

∑_{k=1}^{n} k = n(n+1)/2

439K

∑_{k=1}^{n} k = n(n+1)/2

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

F = G m₁m₂ / r²

297K

∫₀^∞ e^(-t²) dt = √π / 2

128K

det| 6 1 ; 3 7 | = 39