Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:20Z

10γ² + 4γ + 3 = 0

e^{i\pi} + 1 = 0

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

d/dβ [β^11] = 11β^10

6r² + 3r + 1 = 0

186K

d/dt [t^3] = 3t^2

411K

3x² + 4x + 6 = 0

CaCO₃ → CaO + CO₂

448K

2n² + 4n + 0 = 0

22K

CaCO₃ → CaO + CO₂

\lim_{r\to 0} \frac{\sin r}{r} = 1

459K

6ω² + 4ω + 4 = 0

406K

det| 9 4 ; 1 10 | = 86

181K

∫₀^∞ e^(-t²) dt = √π / 2

80K

∑_{k=1}^{n} k = n(n+1)/2

359K