Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:48Z

∇²n = 0

d/dt [t^3] = 3t^2

273K

E = mc²

263K

9r² + 4r + 1 = 0

∇ × E = −∂B/∂t

139K

∂β/∂β = 6β

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 1 4 ; 3 2 | = -10

333K

8ψ² + 7ψ + 0 = 0

160K

11γ² + 3γ + 6 = 0

iħ ∂ψ/∂t = Ĥψ

439K

e^{i\pi} + 1 = 0

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

d/dx [x^3] = 3x^2

297K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

128K

det| 6 1 ; 3 7 | = 39

10ω² + 7ω + 4 = 0

404K