Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:33Z

∇²t = 0

∇ × E = −∂B/∂t

460K

det| 5 2 ; 3 6 | = 24

438K

det| 6 4 ; 3 7 | = 30

∂n/∂θ = 3n

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

ΔS ≥ 0

∫₀^∞ e^(-t²) dt = √π / 2

448K

F = G m₁m₂ / r²

22K

1z² + 3z + 2 = 0

det| 7 4 ; 4 8 | = 40

459K

ω = 2πf

406K

7t² + 3t + 1 = 0

9θ² + 7θ + 4 = 0

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

iħ ∂ψ/∂t = Ĥψ

359K

det| 5 6 ; 2 6 | = 18

455K