Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 22:05Z

3n² + 7n + 7 = 0

N₂ + 3H₂ ⇌ 2NH₃

460K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

438K

∫₀^∞ e^(-ω²) dω = √π / 2

\frac{4}{6} \sum_{i=1}^{n} i^{2}

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

\frac{10}{6} \sum_{i=1}^{n} i^{2}

∫₀^∞ e^(-θ²) dθ = √π / 2

448K

iħ ∂ψ/∂t = Ĥψ

22K

d/dr [r^12] = 12r^11

∇²θ = 0

459K

iħ ∂ψ/∂t = Ĥψ

406K

d/dφ [φ^5] = 5φ^4

8ψ² + 7ψ + 0 = 0

181K

∇ × E = −∂B/∂t

80K

2H₂ + O₂ → 2H₂O