Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 21:08Z
10y² + 2y + 6 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∫₀^∞ e^(-t²) dt = √π / 2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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e^{i\pi} + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\oint_C \vec{F}\cdot d\vec{r} = 0
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λ = h/p
∫₀^∞ e^(-ψ²) dψ = √π / 2
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det| 9 4 ; 1 10 | = 86
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