Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z

∇²n = 0

6ω² + 4ω + 4 = 0

273K

det| 2 8 ; 7 3 | = -50

263K

9r² + 4r + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

139K

iħ ∂ψ/∂t = Ĥψ

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

PV = nRT

333K

det| 9 4 ; 1 10 | = 86

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11γ² + 3γ + 6 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

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det| 5 9 ; 7 6 | = -33

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F = G m₁m₂ / r²

297K

F = ma

128K