Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:26Z

det| 6 5 ; 4 7 | = 22

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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N₂ + 3H₂ ⇌ 2NH₃

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∇²φ = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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e^{i\pi} + 1 = 0

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\frac{9}{2} \sum_{i=1}^{n} i^{2}

iħ ∂ψ/∂t = Ĥψ

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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F = ma

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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8ψ² + 7ψ + 0 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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10ω² + 7ω + 4 = 0

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