Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:32Z

11n² + 5n + 4 = 0

F = ma

460K

F = G m₁m₂ / r²

438K

∫₀^∞ e^(-x²) dx = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

186K

7r² + 8r + 5 = 0

411K

4φ² + 6φ + 2 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

iħ ∂ψ/∂t = Ĥψ

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∫₀^∞ e^(-φ²) dφ = √π / 2

det| 9 4 ; 1 10 | = 86

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∂ψ/∂β = 3ψ

406K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

181K

\lim_{t\to 0} \frac{\sin t}{t} = 1

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