Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 16:14Z

∂ψ/∂φ = 6ψ

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∇ × E = −∂B/∂t

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11ψ² + 2ψ + 6 = 0

11t² + 9t + 7 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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λ = h/p

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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8ψ² + 7ψ + 0 = 0

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\frac{9}{7} \sum_{i=1}^{n} i^{2}

iħ ∂ψ/∂t = Ĥψ

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10t² + 9t + 5 = 0

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\frac{2}{8} \sum_{i=1}^{n} i^{2}

6ω² + 4ω + 4 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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