Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 11:37Z
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
det| 6 4 ; 3 7 | = 30
det| 7 8 ; 4 8 | = 24
186K
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
22K
1z² + 3z + 2 = 0
det| 9 4 ; 1 10 | = 86
459K
7t² + 3t + 1 = 0
det| 7 6 ; 1 8 | = 50
80K
∑_{k=1}^{n} k = n(n+1)/2
359K