Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:51Z

∇²n = 0

∇²r = 0

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iħ ∂ψ/∂t = Ĥψ

263K

9r² + 4r + 1 = 0

e^{i\pi} + 1 = 0

139K

det| 4 7 ; 2 5 | = 6

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

8ψ² + 7ψ + 0 = 0

333K

iħ ∂ψ/∂t = Ĥψ

160K

11γ² + 3γ + 6 = 0

∇ × E = −∂B/∂t

439K

d/dt [t^3] = 3t^2

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\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

e^{i\pi} + 1 = 0

297K

det| 12 6 ; 6 13 | = 120

det| 6 1 ; 3 7 | = 39

e^{i\pi} + 1 = 0

N₂ + 3H₂ ⇌ 2NH₃

∑_{k=1}^{n} k = n(n+1)/2